# 000673-Number-of-Longest-Increasing-Subsequence

### Problem

<https://leetcode.com/problems/number-of-longest-increasing-subsequence/description/>

Given an integer array nums, return the number of longest increasing subsequences.

Notice that the sequence has to be strictly increasing.

Example 1:

Input: nums = \[1,3,5,4,7] Output: 2 Explanation: The two longest increasing subsequences are \[1, 3, 4, 7] and \[1, 3, 5, 7].

Example 2:

Input: nums = \[2,2,2,2,2] Output: 5 Explanation: The length of the longest increasing subsequence is 1, and there are 5 increasing subsequences of length 1, so output 5.

Constraints:

1 <= nums.length <= 2000 -106 <= nums\[i] <= 106

### Solution

```python
class Solution:
    def findNumberOfLIS(self, nums: List[int]) -> int:
        if not nums or len(nums) == 0:
            return 0
        
        n, max_len, res = len(nums), 1, 0
        dp = [1] * n
        cnt = [1] * n
        
        for r in range(n):
            for l in range(r):
                # when right > left, found increase sequence, +1 
                if nums[r] > nums[l]:
                    if dp[l]+1 == dp[r]:
                        cnt[r] += cnt[l]
                    # only when left sequence + 1 > right sequence, right sequence +1
                    elif dp[l]+1 > dp[r]:
                        dp[r] = dp[l] + 1
                        cnt[r] = cnt[l]
            
            if max_len == dp[r]:
                res += cnt[r]
            if max_len < dp[r]:
                max_len = dp[r]
                res = cnt[r]
     
        return res

# 
# [1,3,5,4,7]
# dp = [1, 2, 3, 3, 4]
# cnt = [1, 1, 1, 1, 2]
```


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